If the intensity is increased by 3 dB, it:

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Multiple Choice

If the intensity is increased by 3 dB, it:

Explanation:
Decibel changes reflect logarithmic changes in intensity. A rise of 3 dB corresponds to a doubling of intensity. This comes from the relation ΔdB = 10 log10(I2/I1). Setting ΔdB = +3 gives I2/I1 = 10^(0.3) ≈ 1.995, essentially 2. So the intensity doubles. If it were decreased by 3 dB, it would be about half; a rise of about 4.8 dB would triple the intensity; a decrease of 6 dB would quarter it.

Decibel changes reflect logarithmic changes in intensity. A rise of 3 dB corresponds to a doubling of intensity. This comes from the relation ΔdB = 10 log10(I2/I1). Setting ΔdB = +3 gives I2/I1 = 10^(0.3) ≈ 1.995, essentially 2. So the intensity doubles. If it were decreased by 3 dB, it would be about half; a rise of about 4.8 dB would triple the intensity; a decrease of 6 dB would quarter it.

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